Step 12. 优化玩家输入体验
想必你一定注意到了，总是有玩家会用一些非常讨厌的，无法输入的名字。那么有没有办法优化玩家名输入体验捏？
很简单，我们可以添加这么一个函数
不懂也没关系，这是可选的
lua
local function display_candidates_and_get_selection_resolver_enclosure(disp)
local candidates = coromega:get_all_online_players()
local selectable_candidates = {}
for i, candidate in pairs(candidates) do
local idx = ("%s"):format(i)
local name = candidate:name()
selectable_candidates[idx] = name
disp(("%s: %s"):format(idx, name))
end
return function(selection)
local seleted_candidate = selectable_candidates[selection]
if seleted_candidate then
return seleted_candidate
else
return selection
end
end
end然后修改对应的部分：
lua
player_name = coromega:input("请输入要封禁的玩家名：")
local resolver = display_candidates_and_get_selection_resolver_enclosure(function(info) coromega:print(info) end)
player_name = resolver(coromega:input("请输入要封禁的玩家名, 或输入序号: "))
if not player_name or player_name == "" then
coromega:print("玩家名不能为空")
endlua
player_name = coromega:input("请输入要解封的玩家名: ")
local resolver = display_candidates_and_get_selection_resolver_enclosure(function(info) coromega:print(info) end)
player_name = resolver(coromega:input("请输入要解封的玩家名, 或输入序号: "))
if not player_name or player_name == "" then
coromega:print("玩家名不能为空")
endlua
ban_player_name = caller:ask("请输入要封禁的玩家名：")
local resolver = display_candidates_and_get_selection_resolver_enclosure(function(info) caller:say(info) end)
ban_player_name = resolver(caller:ask("请输入要封禁的玩家名, 或输入序号: "))
if not ban_player_name or ban_player_name == "" then
caller:say("玩家名不能为空")
endlua
ban_player_name = caller:ask("请输入要解封的玩家名: ")
local resolver = display_candidates_and_get_selection_resolver_enclosure(function(info) caller:say(info) end)
ban_player_name = resolver(caller:ask("请输入要解封的玩家名, 或输入序号: "))
if not ban_player_name or ban_player_name == "" then
caller:say("玩家名不能为空")
end输入 reload 然后观察变化，是不是挺好使的？
贡献者
wling